16v^2+40v=-25

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Solution for 16v^2+40v=-25 equation: 



16v^2+40v=-25

We move all terms to the left:

16v^2+40v-(-25)=0

We add all the numbers together, and all the variables

16v^2+40v+25=0

a = 16; b = 40; c = +25;
Δ = b2-4ac
Δ = 402-4·16·25
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$v=\frac{-b}{2a}=\frac{-40}{32}=-1+1/4$

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